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9 March, 14:26

A mysterious rocket-propelled object of mass 45.0 kg is initially at rest in the middle of the horizontal, friction-less surface of an ice covered lake. Then a force directed east and with magnitude F (t) = (16.8 N/s) t is applied. How far does the object travel in the first 5.00 s after the force is applied?

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  1. 9 March, 14:49
    0
    s = 23.34 m

    Explanation:

    given,

    F = 16.8 t

    mass = 45 Kg

    time = 5 s

    distance traveled by the object = ?

    now,

    Force acting at time 5 s

    F = 16.8 x 5

    F = 84 N

    we know,

    F = ma

    84 = 45 x a

    a = 1.867 m/s²

    initial velocity = 0 m/s

    using equation of motion for velocity calculation

    v = u + at

    v = 0 + 1.867 x 5

    v = 9.335 m/s

    again using equation of motion for distance calculation

    v² = u² + 2 a s

    9.335² = 0 + 2 x 1.867 x s

    s = 23.34 m

    distance traveled is equal to 23.34 m.
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