Ask Question
20 May, 11:25

A Venturi tube may be used as the inlet to an automobile carburetor. If an inlet pipe with a diameter of 2.0 cm diameter narrows to diameter of 1.0 cm, determine the pressure drop in the constricted section for an initial airflow of 3.0 m/s in the 2-cm section? (Assume air density is 1.25 kg/m

+4
Answers (2)
  1. 20 May, 11:33
    0
    I think it's 81
  2. 20 May, 12:26
    0
    the pressure drop is equal to 80.99 Pa

    Explanation:

    we have the following dа ta:

    d1 = 2 cm = 0.02 m

    d2 = 1 cm = 0.01 m

    v = 3 m/s

    p = 1.25 kg/m^3

    ΔP = ?

    For the calculation of the pressure drop we will use Bernoulli's principle for the Venturi Tube:

    P1 - P2 = ((v^2*p) / 2) * ((A1^2/A2^2) - 1)

    where A = area

    P1 - P2 = ΔP = ((v1^2*p) / 2) * ((A1^2/A2^2) - 1)

    for the calculation of the areas we will use the following formula:

    A1 = (pi*d1^2) / 4 = (pi * (0.02 m) ^2) / 4 = 0.00031 m^2

    A2 = (pi * (0.01 m) ^2) / 4 = 0.000079 m^2

    ΔP = ((3 m/s) ^2*1.25 kg/m^3) / 2) * ((0.00031 m^2) ^2 / (0.000079 m^2) ^2) - 1) = 80.99 N/m^2 = Pa
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A Venturi tube may be used as the inlet to an automobile carburetor. If an inlet pipe with a diameter of 2.0 cm diameter narrows to ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers