An electron is to be accelerated from a velocity of 4.50*106 m/s to a velocity of 9.00*106 m/s. Through what potential difference must the electron pass to accomplish this?

-2.85 * 10^ (-17) J

Explanation:

Parameters given:

Final velocity, v = 9 * 10^6 m/s

Initial velocity, u = 4.5 * 10^6 m/s

Using the conservation of energy formula, total energy is conserved:

K. Ein + PEin = KEf + PEf

K. Ef - K. Ein = P. Ein - P. Ef

=> - ∆P. E = K. Ef - K. Ein

∆P. E = K. Ein - K. Ef

∆P. E = ½mu² - ½mv²

∆P. E = ½m[ (4.5 * 10^6) ² - (9 * 10^6) ²]

∆P. E = ½ * 9.31 * 10^ (-31) * (-61.25 * 10¹²)

∆P. E = - 2.85 * 10^ (-17) J