A 60-kilogram sled is coasting with a constant velocity of 10 m/s over smooth ice. It enters a rough stretch of ice 6.0 m longs in which the force of friction is 120 N. a) What is the acceleration during this stretch? B) With what speed dies it emerge from the rough patch?

Question

Physics

Mariam

11 December, 15:59

A 60-kilogram sled is coasting with a constant velocity of 10 m/s over smooth ice. It enters a rough stretch of ice 6.0 m longs in which the force of friction is 120 N. a) What is the acceleration during this stretch? B) With what speed dies it emerge from the rough patch?

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Answers (1)

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Gabriella Lawson · Answer 1

-2 m/s²

8.7 m/s

Explanation:

Using Newton's second law, the sum of forces in the x direction:

∑F = ma

-120 N = (60 kg) a

a = - 2 m/s²

Given:

Δx = 6.0 m

v₀ = 10 m/s

a = - 2 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (10 m/s) ² + 2 (-2 m/s²) (6.0 m)

v = 8.7 m/s