Ask Question
13 February, 12:16

Identical balls are dropped from the same initial height and bounce back to half the initial height. In Case 1 the ball bounces off a cement floor and in case 2 the ball bounces off a piece of stretchy rubber. 1) In which case is the average force acting on the ball during the collision the biggest?

+1
Answers (1)
  1. 13 February, 12:59
    0
    Case 1

    Explanation:

    Given : Identical balls are dropped from the same initial height and bounce back to half the initial height

    In case 1 where the the ball bounces off a cement floor, because in this case the time of contact will be less (as compared with time of contact with the stretchy rubber) And hence, a greater force will be felt by the ball (actually impulse will be more).

    impulse I = ΔF/Δt

    ΔF = change in force and Δt = change in time
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Identical balls are dropped from the same initial height and bounce back to half the initial height. In Case 1 the ball bounces off a ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers