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8 May, 16:41

The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of the axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 1.2 m long, and the nerve impulse speed is 27 m/s, how long (in s) does it take for the nerve signal to travel this distance?

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  1. 8 May, 19:03
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    0.044 seconds

    Explanation:

    Parameters given:

    Length of nerve cell = 1.2m

    Nerve impulse speed = 27m/s

    Speed is given as:

    Speed = distance/time

    Therefore, we can make time the subject of the formula. We have:

    Time = distance/speed

    Hence, time taken for the nerve cell to travel this distance is:

    Time = 1.2 / 27

    Time = 0.044 seconds

    It takes 0.044 seconds for the nerve signal to travel the distance of the nerve connecting the spinal cord to the feet.
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