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23 February, 08:49

Calculate the coefficient of kinetic friction for a 1,500 kg car moving at 62 km/h that skids 18 m to rest when its brakes are locked. Speed must be in m/s.

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  1. 23 February, 10:48
    0
    0.84

    Explanation:

    First, convert km/h to m/s.

    62 km/h * (1000 m / km) * (1 h / 3600 s) = 17.2 m/s

    Next, find the acceleration.

    v² = v₀² + 2aΔx

    (0 m/s) ² = (17.2 m/s) ² + 2a (18 m)

    a = - 8.24 m/s²

    Now, find the friction force.

    ∑F = ma

    -F = (1500 kg) (-8.24 m/s²)

    F = 12,400 N

    On a level surface, normal force equals the weight.

    N = mg

    N = (1500 kg) (9.8 m/s²)

    N = 14,700 N

    The coefficient of kinetic friction is therefore:

    μ = F / N

    μ = 12,400 N / 14,700 N

    μ = 0.841

    Rounding to two significant figures, the coefficient of kinetic friction is 0.84.
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