At a distance of 0.218cm from the center of a charged conducting sphere with radius 0.100cm, the electric field is 460N/C. What is the electric field 0.596cmfrom the center of the sphere?

61.54N/C

Explanation:

From the question, the sphere indicates an electric field outside the sphere. This is expressed by:

E=1/4π£0

From this equation, E is inversely proportional to 1/r^2.

As this 1/4π£0 is express as constant and the charge q is contant too, then the expression between electric fields at different distances considering the charge q is expressed as:

E1/E2=r2^2/r1^2

Therefore, E2=E1 (r1^2/r2^2

Substituting the given values into the equation : distance = 0.100cm from the center of the sphere, E1=460N/C, distance of a electric field r1=0.218cm and Electric field, E2, distance of r2 = 0.596cm.

E2 = (r1^2/r2^2)

E2=460N/C ((0.218cm) ^2 / (0.596cm) ^2) = 61.5429NC

E2=61.54N/C.