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12 July, 16:54

72) A coil with a self-inductance of 6.0 H is connected to a dc battery through a switch. As soon as the switch is closed, the rate of change of current is 2.0 A/s. What is the emf induced in this coil at this instant

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Answers (2)
  1. 12 July, 19:16
    0
    E = - 12V

    Explanation:

    Given

    L = self inductance = 6.0H

    di/dt = 2.0A/s

    E = - L * di/dt

    = - 6.0 * 2.0

    = - 12V.
  2. 12 July, 20:38
    0
    12.0 V

    Explanation:

    The E. M. F induced in a coil is given as,

    E = LΔ (i/t) ... Equation 1

    Where E = E. M. F induced in the coil, L = inductance of the coil, Δ (i/t) = rate of change of current when the switch is closed

    Given: L = 6.0 H, Δ (i/t) = 2.0 A/s.

    Substitute into equation 1

    E = 6.0 (2.0)

    E = 12.0 V.

    Hence the emf induced in the coil = 12.0 V
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