A soccer player kicks a ball with initial velocity of 10m/s at an angle of 30 degrees above the horizontal ... what is the magnitude of the vector

Answer: 10m/s^2

Explanation:

Given the following:

Initial Velocity (U) = 10m/s

Angle of inclination = 30°

In other to calculate the magnitude of the vector,

We need to resolve into verti AL and horizontal component.

Vertical component of a vector (Uy) = U * Sinθ

Horizontal component (Ux) = U * Cosθ

Uy = 10 * sin30 = 10 * 0.5 = 5m/s

Ux = 10 * Cos30 = 10 * 0.866 = 8.66m/s

Therefore the magnitude equals:

U = √ (Uy) ^2 + (Ux) ^2

U = √5^2 + 8.66^2

U = √25 + 74.9956

U = √99.9956

U = 9.9997799

U = 10m/s^2