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24 February, 01:09

A soccer player kicks a ball with initial velocity of 10m/s at an angle of 30 degrees above the horizontal ... what is the magnitude of the vector

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  1. 24 February, 03:05
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    Answer: 10m/s^2

    Explanation:

    Given the following:

    Initial Velocity (U) = 10m/s

    Angle of inclination = 30°

    In other to calculate the magnitude of the vector,

    We need to resolve into verti AL and horizontal component.

    Vertical component of a vector (Uy) = U * Sinθ

    Horizontal component (Ux) = U * Cosθ

    Uy = 10 * sin30 = 10 * 0.5 = 5m/s

    Ux = 10 * Cos30 = 10 * 0.866 = 8.66m/s

    Therefore the magnitude equals:

    U = √ (Uy) ^2 + (Ux) ^2

    U = √5^2 + 8.66^2

    U = √25 + 74.9956

    U = √99.9956

    U = 9.9997799

    U = 10m/s^2
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