Ask Question
4 March, 16:39

A constant force of 53 newtons was applied to a 12-kilogram mass for 15 seconds. a.) What was the change in momentum of the mass?

b.) What was the change in velocity of the object?

+2
Answers (1)
  1. 4 March, 19:12
    0
    Impulse = change in momentum

    FΔt = Δp

    (53 N) (15 s) = Δp

    Δp = 795 kg m/s

    For constant mass:

    Δp = m Δv

    795 kg m/s = (12 kg) Δv

    Δv = 66.25 m/s

    Rounding to two significant figures, Δp = 800 kg m/s and Δv = 66 m/s.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A constant force of 53 newtons was applied to a 12-kilogram mass for 15 seconds. a.) What was the change in momentum of the mass? b.) What ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers