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10 March, 12:29

A 111 kg horizontal platform is a uniform disk of radius 1.73 m and can rotate about the vertical axis through its center. A 66.9 kg person stands on the platform at a distance of 1.17m from the center, and a 25.3 kg dog sits on the platform near the person 1.35 m from the center. Find the moment of inertia of this system, consisting of the platform and its population, with respect to the axis.

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  1. 10 March, 12:40
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    Answer:my answer is bacon

    Explanation:bc if bacon is good then ever pig is good
  2. 10 March, 15:15
    0
    The moment of inertia of this system is 303.89 kg * m²

    Explanation:

    Step 1: Data given

    mass of the disk = 111 kg

    radius of the disk = 1.73 m ⇒ formule will be I = 1/2 MR²

    mass of the person = 66.9 kg

    distance form the center = 1.17m

    mass of the dog = 25.3 kg

    distance from the centrer 1.35m

    Step 2: Calculate moment of inertia

    I = ∑Mi * (Ri) ²

    I = I (disk) + I (person) + I (dog)

    Step 3: Calculate moment of inertia of the disk

    I = (1/2) MR² = (1/2) * 111*1.73²

    I = 166.2

    Step 4: Calculate moment of inertia of the person

    I = MR² = 66.9*1.17²

    I = 91.58

    Step 5: Calculate moment of inertia of the dog

    I = MR² = 25.3*1.35²

    I = 46.11

    Step 6 : Calculate moment of inertia

    I = ∑I = 166.2 + 91.58 + 46.11 = 303.89 kg * m²

    The moment of inertia of this system is 303.89 kg * m²
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