Action hero fired from a cannon with conceptual questions Note: for this problem, you can neglect air resistance. An action hero is trying to use a circus cannon to get to the roof on a building 68.9 meters away. She launches herself from the ground with an initial velocity of 34.1 m/s at an angle 59.9 degrees above the horizontal, but instead of landing on the roof she hits the wall of the building. How high up on the wall does she hit?

Question

Physics

Jaelynn Shepard

15 April, 00:36

Action hero fired from a cannon with conceptual questions Note: for this problem, you can neglect air resistance. An action hero is trying to use a circus cannon to get to the roof on a building 68.9 meters away. She launches herself from the ground with an initial velocity of 34.1 m/s at an angle 59.9 degrees above the horizontal, but instead of landing on the roof she hits the wall of the building. How high up on the wall does she hit?

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Olsen · Answer 1

h = 39.3 m

She hit the building wall at 39.3 m high

Explanation:

Given;

Initial velocity u = 34.1 m/s

Direction/angle θ = 59.9°

Horizontal distance d = 68.9 m

Taking the horizontal component of her motion;

d = Ux * t

Ux = ucosθ

d = ucosθ * t

Substituting the values;

68.9 = 34.1cos59.9 * t

t = 68.9/34.1cos59.9

t = 4.03 s

Taking the vertical component of her motion;

h = Uyt - 0.5gt^2

Where h is the height she reached.

g = 9.8m/s^2

Uy = usin59.9

h = (34.1sin59.9 * 4.03) - (0.5*9.8*4.03^2)

h = 39.3 m