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5 November, 21:14

A 2 kg block rests on a 34o incline. If the coefficient of static friction is 0.2, how much additional force, F, must be applied to keep the block from sliding down the incline?

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  1. 5 November, 23:45
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    Reaction force of inclined surface = mg cosθ

    = Friction force acting in upward direction = μ x mg cosθ

    If F be force required in upward direction to keep the block at rest on the plane

    F + μ x mg cosθ = mg sinθ

    F = mg sinθ - μ x mg cosθ

    F = mg (sinθ - μ cosθ)

    = 2 x 9.8 (sin34 - 0.2 cos34)

    = 19.6 (.559 -.1658)

    = 7.7 N

    This is the minimum force required.
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