The high-pressure air storage tank for a supersonic wind tunnel has a volume of 1000 ft3. If air is stored at a pressure of 30 ATM and a temperature of 530R, what is the mass of gas stored in the tank in slugs?

69.86 slugs

Explanation:

From the ideal gas equation

PV = nRT

n (number of moles) = PV/RT

P is pressure of the gas = 30 atm = 30*101325 = 3,039,750 Pa

V is volume of the gas = 1000 ft^3 = 1000/3.2808^3 = 28.32 m^3

R is gas constant = 8.314 J/mol. K

T is the temperature of the gas = 530 R = 5/9 * 530 = 294.44 K

n = 3,039,750*28.32/8.314*294.44 = 35166.11 mol

mass = n * MW

MW of air = 29 g/mol

mass = 35166.11 * 29 = 1019817.19 g * 0.0685 slug/1000 g = 69.86 slugs