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10 April, 11:33

Calculate energy absorbed from your body if you (a) eat 1.0 kg of - 10 oC snow which your body warms to a body temperature of 37 oC. (b) You melt 1.0 kg of - 10 oC snow using a stove and drink the resulting 1.0 kg of water at 2 oC, which your body has to warm to 37 oC.

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  1. 10 April, 14:31
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    (a) 164.5 kJ.

    (b) 122.5 kJ

    Explanation:

    Specific Heat Capacity: The specific heat capacity of a substance, is the quantity of heat required to raise the temperature of a unit mass (1 kg) of a substance through a degree rise in temperature (1 K). It is expressed in J/kgK

    Mathematically, it can be expressed as

    Q = cmΔT.

    Where Q = quantity of heat, c = specific heat capacity, m = mass of the substance, ΔT = change in temperature

    (a) Q = cmΔT

    Where c = specific heat capacity of the body = 3.5 kJ/kgK = 3500 J/kgK, m = 1.0 kg,

    ΔT = T₂ - T₁ = 37 - (-10) = 37+10 = 47 °C

    Substituting this values in the equation above,

    Q = 3500*1.0*47

    Q = 164500 J

    Q = 164.5 kJ.

    Therefore, Energy absorbed by the body = 164.5 kJ

    (b) Q = cmΔT

    Where Q = quantity of heat, c = specific heat capacity of the the body = 3.5 kJ/kgK = 3500 J/kgK, m = 1.0 kg,

    ΔT = T₂ - T₁ = 37 - 2 = 35 °C.

    ∴ Q = 3500*1.0*35

    Q = 122500 J

    Q = 122.5 kJ

    ∴ Energy absorbed by the body = 122.5 kJ
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