A car travels in the + x-direction on a straight and level road. For the first 4.00 s of its motion, the average velocity of the car is vav-x = 6.25 m/s. How far does the car travel in 4.00 s?

25 m

Explanation:

The relationship between Velocity, distance and time is given as

S = v/t ... Equation 1

Where S = average velocity of the car, d = distance covered by the car, t = time

Making d the subject of the equation,

d = vt ... Equation 2

Given: v = 6.25 m/s, t = 4.00 s.

Substitute into equation 2,

d = 6.25 (4)

d = 25 m.

Hence, the distance traveled by the car = 25 m