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11 September, 06:40

A car travels in the + x-direction on a straight and level road. For the first 4.00 s of its motion, the average velocity of the car is vav-x = 6.25 m/s. How far does the car travel in 4.00 s?

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  1. 11 September, 09:09
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    25 m

    Explanation:

    The relationship between Velocity, distance and time is given as

    S = v/t ... Equation 1

    Where S = average velocity of the car, d = distance covered by the car, t = time

    Making d the subject of the equation,

    d = vt ... Equation 2

    Given: v = 6.25 m/s, t = 4.00 s.

    Substitute into equation 2,

    d = 6.25 (4)

    d = 25 m.

    Hence, the distance traveled by the car = 25 m
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