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11 December, 14:57

A truck travels 1430 m uphill along a road that makes a constant angle of 5.76◦ with the horizontal.

Find the magnitude of the truck's horizon - tal component of displacement.

Answer in units of m.

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Answers (1)
  1. 11 December, 17:47
    0
    The horizontal component of displacement is d' = 1422.7 m

    Explanation:

    Given data,

    The distance covered by the truck, d = 1430 m

    The angle formed with the horizontal, Ф = 5.76°

    The displacement is a vector quantity.

    The horizontal component of displacement is given by,

    d' = d cos Ф

    = 1430 cos 5.76°

    = 1422.7 m

    Hence, the horizontal component of displacement is d' = 1422.7 m
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