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15 November, 07:11

The current through two identical light bulbs connected in a series is 0.25 amps. The voltage across both bulbs is 100 volts. Find the resistance of a single light bulb.

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  1. 15 November, 09:04
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    Answer: 200ohms

    Explanation:

    According to Ohm's law, the current (I) passing through a metallic conductor is directly proportional to the potential difference (v) between its ends at constant temperature and pressure. Mathematically, E=IRt

    Where E is the voltage across both bulbs, I is the current, Rt is the total equivalent resistance

    E = 100V, I = 0.25amps Rt = R+R (since they are 2 identical bulbs in series, we will add them together)

    Rt = 2R

    Substituting this values in the formula to get R, we have;

    100 = 0.25 (2R)

    100 = 0.5R

    R = 100/0.5

    R = 200ohms

    The resistance of a single light bulb will be 200ohms.

    Note that the unit of resistance is ohms
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