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16 January, 07:52

A simple AC generator consists of a single loop of wire rotating 50 times per second within a magnetic field. The loop is a rectangle 5cm by 12 cm. The field strength is 0.21 T. What is the peak output emf?

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  1. 16 January, 10:27
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    39.56 x 10⁻² V

    Explanation:

    Peak emf in a rotating coil

    = n BAω

    Where n is no of turns of coil, B is magnetic field, A is area of coil and ω is angular velocity of rotation of coil

    Here n = 1

    B =.21 T

    A = 5 X 12 X 10⁻⁴ = 60 X 10⁻⁴

    ω = 2π X 50 = 100π

    Emf = 1 x. 21 x 60 x 10⁻⁴ x 100 x 3.14

    = 39.56 x 10⁻² V
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