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12 June, 07:56

A basketball player makes a bounce pass by throwing the ball with a speed of 5.3 m/s and at an angle 12° below the horizontal. It leaves her hands 1.0 m above the floor. Calculate how far omher feet the ball hits the ground.

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  1. 12 June, 09:07
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    ball hit the ground from her feet is 1.83 m far away

    Explanation:

    given data

    speed = 5.3 m/s

    angle = 12°

    height = 1 m

    to find out

    how far from her feet ball hit ground

    solution

    we consider here x is horizontal component and y is vertical component

    so in vertical

    velocity will be = v sin12

    vertical speed u = 5.3 sin 12 = 1.1 m/s downward

    and

    in horizontal, velocity we know v = 5.3 m/s

    so from motion of equation

    s = ut + 0.5*a*t²

    s is distance t is time a is 9.8

    put all value

    1 = 1.1 (t) + 0.5*9.8*t²

    solve it we get t

    t = 0.353 s

    and

    horizontal distance is = vcos12 * t

    so horizontal distance = 5.3*cos12 * (0.353)

    horizontal distance = 1.83 m

    so ball hit the ground from her feet is 1.83 m far away
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