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30 December, 18:43

A loop circuit has a resistance of R1 and a current of 1.9 A. The current is reduced to 1.5 A when an additional 3.1 Ω resistor is added in series with R1. What is the value of R1? Answer in units of Ω.

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  1. 30 December, 20:30
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    11.625 Ohm

    Explanation:

    Let V be the Voltage charge of the loop, as this is constant we know that before the resistor addition the current I is:

    V/R1 = 1.9 or V = 1.9R1

    After the resistor addition to series R = R1 + 3.1

    I = V/R = V / (R1 + 3.1) = 1.5

    We can substitute V = 1.9R1

    1.9R1 = 1.5R1 + 1.5*3.1

    0.4R1 = 4.65

    R1 = 4.65/0.4 = 11.625 Ohm
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