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20 February, 07:35

A bullet fired straight through a board 0.10 m thick strikes the board with a speed of 480 m/s and emerges with a speed of 310 m.

Part A

What is the x component of the average acceleration of the bullet while in the board? The positive x direction is the initial direction of motion of the bullet.

Express your answer with the appropriate units.

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Answers (1)
  1. 20 February, 08:22
    0
    givens

    vf = 310 m/s

    vi = 480 m/s

    d = 0.1 m

    formula

    vf^2 = vi^2 + 2*a*d

    Solution

    310^2 (m/s) ^2 = 480^2 (m/s) ^2 + 2 * a * 0.1 meters

    96100 = 230400 + 2*a * 0.1

    96100 - 230400 = 2*a*0.1

    -134300 = 2*0.1*a

    -134300 = 0.2 * a

    -134300/0.2 = a

    a = - 671500 m/s^2

    The important thing to notice is that the acceleration is minus which means the bullet is slowing down.
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