Raul dug a hole in his yard to repair a water pipe. It took him 2 seconds to apply a force of 50 Newtons to push the shovel 0.25 m into the ground.

How much power was used?

A 0.01 watts

B. 6.25 J/S

C. 25.00 N-m-s

D. 100.00 watts

Question

Physics

Adams

23 September, 07:59

Raul dug a hole in his yard to repair a water pipe. It took him 2 seconds to apply a force of 50 Newtons to push the shovel 0.25 m into the ground.

How much power was used?

A 0.01 watts

B. 6.25 J/S

C. 25.00 N-m-s

D. 100.00 watts

+3

Answers (1)

Know the Answer?

Tiffany Mccullough · Answer 1

Option B. 6.25 J/S

Explanation:

Data obtained from the question include:

t (time) = 2secs

F (force) = 50N

d (distance) = 0.25m

P (power) = ?

The power can be obtained by using the formula P = workdone/time.

P = workdone / time

P = (50 x 0.25) / 2

P = 6.25J/s

Raul dug a hole in his yard to repair a water pipe. It took him 2 seconds to apply a force of 50 Newtons to push the shovel 0.25 m into the ground.How much power was used?A 0.01 wattsB. 6.25 J/SC. 25.00 N-m-sD. 100.00 watts

Raul dug a hole in his yard to repair a water pipe. It took him 2 seconds to apply a force of 50 Newtons to push the shovel 0.25 m into the ground.

How much power was used?

A 0.01 watts

B. 6.25 J/S

C. 25.00 N-m-s

D. 100.00 watts