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3 August, 22:22

Water is contained in a closed, rigid 0.2 m 3 tank at an initial pressure of 5 bar and a quality of 50%. Heat transfer occurs until the tank contains only saturated vapor. Determine the final mass of vapor in the tank, in kg, and the final pressure, in bar.

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  1. 3 August, 22:48
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    Final mass=0.89kg

    Final pressure=5.6bar

    Explanation:

    To find mass, m=v/v1

    But v1=vf + x (vg-vf)

    Vf = 0.001093m^3/kg

    Vg = 0.3748m^3/kg

    V1 = 0.001093+0.5 (0.3748-0.001093)

    V1 = 0.225m^3/kg

    M = 0.20/0.225 = 0.89kg

    Final pressure will be:

    V/V1 = P/P1

    Cross multiply

    VP1=V1P

    P1 = 0.225*5/0.2

    P1=:5.6 bar
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