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13 September, 14:49

A 1.6-m wire is wound into a coil with a radius of 3.2cm.

-If this coil is rotated at 93 rpm in a (7.1x10^-2) - T magnetic field, what is it's maximum emf? (In 2 significant figures in mV)

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  1. 13 September, 15:47
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    18 mV

    Explanation:

    The maximum emf is:

    ε = N B A ω

    where N is the number of turns in the coil,

    B is the strength of the magnetic field,

    A is the area of the coil,

    and ω is the angular velocity.

    The number of turns N is equal to the length of the wire divided by the circumference of the coil.

    N = L / (2πr)

    Area of the coil is:

    A = πr²

    The angular velocity in rad/s is:

    ω = rpm * 2π / 60 s

    Therefore:

    ε = (L / (2πr)) B (πr²) (rpm * 2π / 60 s)

    ε = L B r (rpm * π / 60 s)

    Plugging in values:

    ε = (1.6 m) (0.071 T) (0.032 m) (93 * π / 60 s)

    ε = 0.018 Tm²/s

    ε = 18 mV
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