A solid conducting sphere of radius 2.00 cm has a charge of 8.40 µC. A conducting spherical shell of inner radius 4.00 cm and outer radius 5.00 cm is concentric with the solid sphere and has a charge of - 2.55 µC. Find the electric field at the following radii from the center of this charge configuration.

Question

Physics

Talan

11 August, 13:02

A solid conducting sphere of radius 2.00 cm has a charge of 8.40 µC. A conducting spherical shell of inner radius 4.00 cm and outer radius 5.00 cm is concentric with the solid sphere and has a charge of - 2.55 µC. Find the electric field at the following radii from the center of this charge configuration.

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Answers (1)

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Isabella Stewart · Answer 1

Answer: the electric field is equal to: E=0 for r<2 cm; E = - 2.29*10^4/r^2 for 2cm
the electric field in N/C units

Explanation: In order to find the electric field for all r values, we have to use the definition of electric field and Gaussian law.

In this sense, for r<2 cm as it is inside a conductor teh electric field is zero.

for 2cm< r< 4 cm we applied the field from a spherical charge distribution so by the Gaussian law we find the total charge inside the gaussian surface so

E. 4π r^2 = Q inside/ε0 = - 2.55μC/ε0

Idem for other regions.

for 4 cm
Finally, for r>5 cm

E. 4π r^2=Q inside/ε0 = (8.40-2.55) μC/ε0