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22 January, 13:29

A 5 kg fish swimming at 1 m/s swallows an absentminded 500 g fish swimming toward it at a veloc - ity that brings both fish to a halt immediately after lunch. What is the velocity of the approaching smaller fish before lunch?

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  1. 22 January, 14:58
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    v = 10 m/s

    Explanation:

    given,

    Mass of large fish, M = 5 Kg

    speed of swimming, v' = 1 m/s

    mass of small fish, m = 500 g = 0.5 Kg

    speed of the fish = v

    using conservation of momentum

    m v + M v' = M u' + m u

    final speed of both the speed is zero.

    - 0.5 x v + 5 x 1 = 0

    negative sign is used because small fish is moving in opposite direction.

    now,

    0.5 v = 5

    v = 10 m/s

    hence, the speed of the small fish is equal to 10 m/s.
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