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13 June, 12:58

A self-driving car traveling along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 32.0 m/s. Then the vehicle travels for 53.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s. (a) How long is the self-driving car in motion (in s) ? s (b) What is the average velocity of the self-driving car for the motion described? (Enter the magnitude in m/s.) m/s

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  1. 13 June, 13:52
    0
    t = 75.4 s

    v = 26.9 m/s

    Explanation:

    Part1:

    v1 = 0 m/s

    v2 = 32 m/s

    a = 2 m/s2

    The time needed to reach the final speed is:

    v2 = v1 + a*t

    32 = 0 + 2*t

    t = 16 s

    Part 2:

    constant speed of 32 m/s for 53 s

    Part 3:

    v2 = 32 m/s

    v3 = 0 m/s

    t = 5 s

    The acceleration is negative because the car is stopping:

    v3 = v2 + a*t

    0 = 32 + a*5

    a = - 6.4 m/s

    a) The total time the car is in motion is:

    total time = 16 + 53 + 6.4 = 75.4 s

    b) For the average speed you can calculate the total distance and divide it by the total time for an easier way

    Part 1

    d = (32+0) / 2 * 16 = 256 m

    Part 2

    d = 32 * 53 = 1696 m

    Part 3

    d = (32+0) / 2 * 5 = 80 m

    Average speed:

    v = (256 + 1696 + 80) / 75.4 = 26.9 m/s
  2. 13 June, 14:50
    0
    V=26.9 m/s

    T=75.4s good luck
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