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5 March, 08:56

If 10 calories of energy are added to 2 grams of ice at - 30° C, calculate the final temperature of the ice. (Notice that the specific heat of ice is different from that of water.) T. F =

-20° C

-30° C

30° C

40° C

+2
Answers (1)
  1. 5 March, 12:41
    0
    -20°C

    Explanation:

    ΔQ = m c Δt

    here ΔQ is heat supplied which is 10 calories, m is mass which is 2 g, c is specific heat capacity of ice which is 0.5 cal / (g C°), Δt is change in temperature which here is to be calculated.

    re arranging the equation we get

    Δt = ΔQ / (mc)

    = 10 / (2 * 0.5)

    = 10/1

    = 10 C°

    final temperature = - 30 + 10 = - 20°C

    hence option is A
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