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29 October, 13:06

A squirrel runs along an overhead telephone wire that stretches from the top of one pole to the next. It is initially at position x i = 3.47 m, as measured from the center of the wire segment. It then undergoes a displacement of Δx = - 6.29 m. What is the squirrel's final position xf?

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  1. 29 October, 13:14
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    The the squirrel's final position is - 2.82 m

    Explanation:

    ΔX = Xf - Xi

    Where;

    ΔX is the displacement in the squirrel's position = - 6.29 m

    Xf is the the squirrel's final position = ?

    Xi is the the squirrel's initial position = 3.47 m

    From the equation above

    Xf = ΔX + Xi

    Xf = ( - 6.29 + 3.47) m

    Xf = - 2.82 m

    Therefore, for a squirrel with an initial position of 3.47 m and displacement in position as - 6.29 m, the final position will be - 2.82 m
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