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26 May, 00:34

How much work did the movers do (horizontally) pushing a 41.0-kgkg crate 10.6 mm across a rough floor without acceleration, if the effective coefficient of friction was 0.60?

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  1. 26 May, 02:04
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    W=2.60 J

    Explanation:

    Given that

    m = 41 kg

    d = 10.6 mm

    Coefficient of friction = 0.6

    Friction force, Fr=μ m g

    Fr = 0.6 x 41 x 10 N (take g = 10 m/s²)

    Fr = 246 N

    We know that work done by a force given as

    W = F. d

    Now by putting the values

    W = 246 x 10.6 x 10 ⁻³ J

    W=2.60 J

    Therefore the work done by movers in the horizontal direction will be 2.60 J. The mover does the work against the friction force.
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