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1 August, 19:03

During a very quick stop, a car decelerates at 7.00 m/s2. What is the angular acceleration of its 0.280-m-radius tires, assuming they do not slip on the pavement

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  1. 1 August, 21:37
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    Answer: - 25 rad/s²

    Explanation: The linear acceleration (a) is related to angular acceleration (α) is given as

    a = αr

    -7.00 = α (0.280)

    α = - 7 / 0.280 = - 25 rad/s²

    The negative sign denotes deceleration
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