A spherical party balloon is being inflated with helium pumped in at a rate of 4 cubic feet per minute. How fast is the radius growing at the instant when the radius has reached 2 ft

Question

Physics

Kenya Maynard

17 August, 01:03

A spherical party balloon is being inflated with helium pumped in at a rate of 4 cubic feet per minute. How fast is the radius growing at the instant when the radius has reached 2 ft

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Answers (1)

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Adelaide Barber · Answer 1

0.159 ft/min

Explanation:

v = 4/3πr³

dv/dt = 8

dv/dt = 4/3π (3r²) (dr/dt)

plugging the values

8=4/3π (3r²) (dr/dt)

dr/dt = 1 / (6.28) = 0.159 ft per min approx