If a diver's lungs have a volume of 6.00 L at the surface of the water, what is their volume at a depth of 125 m?

0.458 L

Explanation:

Volume at surface, V = 6 L

Pressure at surface, P = Po = 1.01 x 10^5 Pa

Depth, h = 125 m

Let the volume is V'

Pressure at depth, P' = Po + h x d x g

Where, d is the density of water

P' = 1.013 x 10^5 + 125 x 1000 x 9.8

P' = 13.263 x 10^5 Pa

By the law

P' x V' = P x V

13.263 x V' = 1.013 x 10^5 x 6

V' = 0.458 L

thus, the volume is 0.458 L.

volume at a depth of 125 m is 0.48 liters

Explanation:

given data

volume V1 = 6.00 L

depth = 125 m

solution

we consider here pressure at top P1 is 1 atm and at depth P2 = 12.5 atm

we use here equation that is

P1 * V1 = P2 * V2 ... 1

put here value

1 * 6 = 12.5 * V2

solve it and we get here

V2 = 0.48 liters

so volume at a depth of 125 m is 0.48 liters