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17 August, 23:21

Light of wavelength 480 nm illuminates a double slit, and the interference pattern is observed on a screen. At the position of the m = 4 bright fringe, how much farther is it to the more distant slit than to the nearer slit?

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  1. 18 August, 03:18
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    BC = 980nm

    Explanation:

    Given wavelength = 490nm

    m=2

    Required to find (OB - OC) = BC (more distant slit - nearest slit) = dsin theta

    We have dsin theta = m*wavelength

    or BC = m * wavelength = 2*490nm

    = 980nm = 98.000A
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