A 10-kg mass slides down a flat hill that makes an angle of 10° with the horizontal. If friction is negligible, what is the resultant force on the sled?

Resultant force = 17.02 N

Explanation:

As we assume the coefficient of friction is negligible, the normal force won't affect the resultant force.

As a result of this, the sine of the angle times the force of gravity on the 10 kg mass is equal to the resultant force, which is, force due to gravity = m * a = 10 kg * 9.8 m/s² = 98 N

98 sin (10) = ?

Sin (10) = 0.1736

98 x 0.1736 = 17.02 N.

Therefore, the resultant force = 17.02 N