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2 February, 19:40

A motorcycle starts from rest and has a constant acceleration. In a time interval t, it undergoes a displacement x and attains a final velocity v. then t is increased so that the displacement is 3x. What final velocity does the motorcycle attain?

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  1. 2 February, 21:12
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    √ (6ax)

    Explanation:

    Hi!

    The question states that during a time t the motorcyle underwent a displacement x at constant acceleration a starting from rest, mathematically we can express it as:

    x = (1/2) at^2

    Then the we need to find the time t' for which the displacement is 3x

    3x = (1/2) a (t') ^2

    Solving for t':

    t'=√ (6x/a)

    Now, the velocity of the motorcycle as a function of time is:

    v (t) = a*t

    Evaluating at t=t'

    v (t') = a*√ (6x/a) = √ (6*x*a)

    Which is the final velocity

    Have a nice day!
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