A light bulb provides a resistance of 20 Ω to the 30 A current that runs through it. Determine the voltage of the battery in the flashlight.

0.7 V

2 V

51 V

600 V

The voltage of the battery in the flashlight is 600 v

Explanation:

A light bulb provides a resistance of 20 Ω to the 30 A current that runs through it. Determine the voltage of the battery in the flashlight.

To determine the voltage of this battery, all we need to do is to use the formula;

V = IR

where v = voltage

I = current

R = resistance

From the question given;

resistance (I) is given to be 20 while current (I) is 30

We can now proceed to insert our values into the formula;

V = IR

V = 20 * 30

v = 600 v

The voltage of the battery in the flashlight is 600 v

Ohm's law:

V = IR

V = (30 A) (20 Ω)

V = 600 V