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7 February, 14:55

What do I have to do to figure out " What % of an object's mass is above the water line if the object's density is 0.82g/ml " with just that information?

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  1. 7 February, 15:12
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    18%

    Explanation:

    There are two equal and opposite forces on a floating object: weight and buoyancy.

    W = B

    The weight of an object is its mass times gravity: W = mg

    Buoyancy is the weight of the displaced fluid: W = mf g

    Plugging in:

    mg = mf g

    m = mf

    Mass is density times volume:

    ρV = ρf Vf

    Solving for the ratio of Vf / V:

    Vf / V = ρ / ρf

    Given that ρ = 0.82 g/mL and ρf = 1.00 g/mL:

    Vf / V = 0.82

    That means 82% of the object's volume (and therefore, 82% of its mass, assuming uniform density) is submerged. Which means that 18% is above the water line.
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