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4 October, 10:53

An object initially at rest experiences an acceleration of 12 m/s2 for a time of 5 s. How far will it travel during that time?

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  1. 4 October, 11:36
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    150 meters

    Explanation:

    d =.5a*t^2 + v0*t

    d = displacement

    v0 = initial velocity, 0 because the object was initially at rest

    a = acceleration, which is 12

    t = time, which is 5

    d = (12/2) * (5^2) + 0 = 6*25 = 150
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