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16 July, 21:11

It requires 0.30 kJ of work to fully drive a stake into the ground. If the average resistive force on the stake by the ground is 828 N, how long is the stake?

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  1. 16 July, 23:07
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    Length of the stake will be 0.3623 m

    Explanation:

    We have given energy required to fully drive a stake into ground = 0.30 KJ = 300 J

    Average resistive force acting on the floor is equal to F = 828 N

    We have to find the length of the stake

    We know that work done is given by

    W = Fd, here W is work done, F is average force and d is the length of the stake

    So 300 = 828*d

    d = 0.3623 m

    So length of the stake will be 0.3623 m
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