Ask Question
Today, 04:04

A 4.2 cm diameter circular loop of wire is in a 1.14 T magnetic field. The loop is removed from the field in 0.18 s. Assume that the loop is perpendicular to the magnetic field. What is the average induced emf?

+4
Answers (1)
  1. Today, 06:19
    0
    Given Information:

    Diameter of loop = d = 4.2 cm = 0.042 m

    Magnetic field = B = 1.14 T

    Time = Δt = 0.18 s

    Required Information:

    EMF = ?

    Answer:

    EMF = 0.417 V

    Explanation:

    The Faraday's Law of Induction relates induced EMF and the time rate of change of magnetic flux which is given by

    EMF = - ΔФ/Δt

    EMF = - AΔB/Δt

    Where A is the area of circular loop and ΔB is the change in magnetic field

    A = πr²

    A = π (d/2) ²

    A = π (0.042/2) ²

    A = 0.0659 m²

    EMF = - 0.0659 * (0 - 1.14) / 0.18

    EMF = - 0.0659 * (-1.14) / 0.18

    EMF = 0.417 V

    Therefore, the average induced EMF in circular loop of wire is 0.417 Volts
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 4.2 cm diameter circular loop of wire is in a 1.14 T magnetic field. The loop is removed from the field in 0.18 s. Assume that the loop ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers