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13 March, 02:30

A 4.65 g bullet moving at 824 m/s penetrates a tree to a depth of 5.23 cm. Use energy considerations to find the average frictional force that stops the bullet. Answer in units of N.

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  1. 13 March, 05:18
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    30183.92 N

    Explanation:

    Force: This can be defined as the product of the mass of a body and it's acceleration. The S. I unit of force is Newton (N).

    From the question,

    The kinetic energy of the bullet = Work done by friction in the tree in stopping the bullet.

    1/2mv² = Fₓd ... Equation 1

    Where m = mass of the bullet, v = velocity of the bullet, Fₓ = average Frictional force exerted by the tree on the bullet, d = depth of penetration.

    Make Fₓ the subject of the equation,

    Fx = mv²/2d ... Equation 2

    Given: m = 4.65 g = 0.00465 kg, v = 824 m/s, d = 5.23 cm = 0.0523 m.

    Substitute into equation 2

    Fₓ = 0.00465 (824) ² / (2*0.0523)

    Fₓ = 30183.92 N.

    Hence the average frictional force = 30183.92 N
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