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7 February, 11:10

Compute your average velocity in the following two cases: (a) You walk 50.2 m at a speed of 2.21 m/s and then run 50.2 m at a speed of 4.11 m/s along a straight track. (b) You walk for 1.00 min at a speed of 2.21 m/s and then run for 1.16 min at 4.11 m/s along a straight track.

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  1. 7 February, 13:43
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    a) 2.87 m/s

    b) 3.23 m/s

    Explanation:

    The avergare velocity can be found dividing the length traveled d by the total time t.

    a)

    For the first part we easily know the total traveled length which is:

    d = 50.2 m + 50.2 m = 100.4 m

    The time can be found dividing the distance by the velocity:

    t1 = 50.2 m / 2.21 m/s = 22.7149 s

    t2 = 50.2 m / 4.11 m/s = 12.2141 s

    t = t1 + t2 = 34.9290 s

    Therefore, the average velocity is:

    v = d/t = 2.87 m/s

    b)

    Here we can easily know the total time:

    t = 1 min + 1.16 min = 129.6 s

    Now the distance wil be found multiplying each velocity by the time it has travelled:

    d1 = 2.21 m/s * 60 s = 132.6 m

    d2 = 4.11 m/s * (1.16 * 60 s) = 286.056 m

    d = 418.656 m

    Therefore, the average velocity is:

    v = d/t = 3.23 m/s
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