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1 May, 04:46

A runner starts jogging with an initial velocity of 0.85 m/s and eventually reaches with a final velocity of 5.2 m/s. This change in velocity occurs over a displacement of 12.0 m. What is his acceleration?

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  1. 1 May, 05:38
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    The answer to your question is: a = 1.1 m/s²

    Explanation:

    Data

    v1 = 0.85 m/s

    v2 = 5.2 m/s

    displacement = 12.0 m

    a = ?

    Formula

    v2² = v1² + 2ad

    a = (v2² - v1²) / 2d

    Process

    a = (5.2² - 0.85²) / (2) (12)

    a = (27.04 - 0.72) / 24

    a = 26.32 / 24

    a = 1.1 m/s²
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