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3 January, 10:12

Suppose that you charge a 5 F capacitor in a circuit containing nine 4.5 V batteries, so the final potential difference across the plates is 40.5 V. How much charge is on each plate

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  1. 3 January, 13:36
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    The charge is on each plate is 202.5 C

    Explanation:

    Given;

    capacitance, C = 5 F

    voltage of each battery = 4.5 V

    total potential across the plates, V = 40.5 V

    From the total potential given, it can be concluded that the circuit is in series. The charge on each plate is the same.

    Q = CV

    Where;

    Q is the charge on each plate

    C is the capacitance

    V is the total potential across the plates

    Q = 5 x 40.5

    Q = 202.5 C

    Therefore, the charge is on each plate is 202.5 C
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