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7 June, 01:26

A current of I = 3.8 A is passing through a conductor with cross sectional area A = 2.5 x 10^-4 m^2. The charge carriers in the conductor, electrons, have a number density n = 1.3 x 10^27 m^-3.

(a) Express the drift velocity of electrons through 1. A. n, and the fundamental charge e.

(b) Calculate the numerical value of v, in m/s.

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  1. 7 June, 04:31
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    current, i = 3.8 A

    Area of crossection, A = 2.5 x 10^-4 m²

    number density, n = 1.3 x 10^27 m^-3

    (a) the relation between the current and the drift velocity is given by

    i = n e A v

    where, e is the electronic charge, A be the area of crossection area of the wire and v be the drift velocity

    v = i / neA

    (b)

    3.8 = 1.3 x 10^27 x 1.6 x 10^-19 x 2.5 x 10^-4 x v

    3.8 = 52000 v

    v = 7.3 x 10^-5 m/s
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