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23 October, 16:29

A sled and rider, gliding over horizontal, frictionless ice at 4.5 m/s, have a combined mass of 74 kg. The sled then slides over a rough spot in the ice, slowing down to 2.6 m/s. What impulse was delivered to the sled by the friction force from the rough spot?

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  1. 23 October, 19:00
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    J = 525.4 Kg. m/s

    Explanation:

    given,

    mass of the sled, m = 74 Kg

    initial speed of the sled, v = 4.5 m/s

    final speed of the sled, u = 2.6 m/s

    Impulse = ?

    Impulse is equal to change in momentum.

    J = initial momentum - final momentum

    J = m (v - u)

    final speed, u = - 2.6 m/s

    J = 74 x (4.5 - (-2.6))

    J = 74 x 7.1

    J = 525.4 Kg. m/s

    Hence, the impulse delivered by the sled is equal to 525.4 kg. m/s
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