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16 July, 02:42

We know that the Moon revolves around Earth during a period of 27.3 days. The average distance from the center of Earth to the center of the Moon is 3.84*108 m.

1) What is the magnitude of the acceleration of the Moon due to its motion around Earth?

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  1. 16 July, 03:12
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    This is a circular motion questions

    Where the oscillation is 27.3days

    Given radius (r) = 3.84*10^8m

    Circular motion formulas

    V=wr

    a=v^2/r

    w=θ/t

    Now, the moon makes one complete oscillation for 27.3days

    Then, one complete oscillation is 2πrad

    Therefore, θ=2πrad

    Then 27.3 days to secs

    1day=24hrs

    1hrs=3600sec

    Therefore, 1day=24*3600secs

    Now, 27.3days = 27.3*24*3600=2358720secs

    t=2358720secs

    Now,

    w=θ/t

    w=2π/2358720 rad/secs

    Now,

    V=wr

    V=2π/2358720 * 3.84*10^8

    V=1022.9m/s

    Then,

    a=v^2/r

    a=1022.9^2/*3.84*10^8

    a=0.0027m/s^2
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